A painter drops a bucket from a ladder on the side of a building. The acceleration of gravity is 9.8 m/s
What is the speed (m/s) of the falling bucket after 2.42 seconds?
(neglect drag force)
Any help is appreciated! :)
2007-09-15 07:18:39 · 5 answers · asked by Catalina 2 in Science & Mathematics ➔ Physics
Finding SPEED, not velocity
2007-09-15 08:34:26 · update #1
v = u + at is the formula to be used here, where u is the initial velocity, a the acceleration, t the time and v the final velocity.
v = 0 + 9.8 x 2.42 (since the initial velocity is zero)
= 23.716 m/s
2007-09-15 08:16:54 · answer #1 · answered by Swamy 7 · 0⤊ 0⤋
Finding Speed From Acceleration
2016-11-04 12:45:30 · answer #2 · answered by ? 4 · 0⤊ 0⤋
You can use final velocity, v = u + at
where u, initial velocity is zero and a, acceleration is 9.8 and t, time is 2.42 seconds.
v = 23.716 m/s
Here speed and velocity maybe used interchangeably as the direction is specified to be downwards.
2007-09-15 20:00:54 · answer #3 · answered by ? 6 · 0⤊ 0⤋
For the best answers, search on this site https://shorturl.im/aw1NP
the formula: acceleration: final velocity-initial velocity / time speed: distance/time velocity: basically speed, distance/time
2016-04-10 22:12:59 · answer #4 · answered by Anonymous · 0⤊ 0⤋
v = u + at
velocity (after) = inital velcity + acceleration (time)
initial velocity is zero here so find a X t
2007-09-15 07:23:15 · answer #5 · answered by Etymologist 3 · 0⤊ 0⤋