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What is the distance between point A (6,4) and point B (-2,-2)?

2007-09-15 06:24:19 · 8 answers · asked by Kaylin H 1 in Science & Mathematics Mathematics

8 answers

This is an application of the Pythagorean Theorem.
If you plot these 2 points on graph paper, you will see that the horizontal distance is 6 units. The vertical distance is also 6 units. The hypotenuse is therefore
sq.rt.(6^2+6^2), =sq.rt(72), =6rt2
Mathematically, the formula is
d^2 =[y(2)-y(1)]^2 +[x(2)-x(1)]^2
d, of course, is obtained by taking the sq.rt. of both sides.

2007-09-15 06:38:09 · answer #1 · answered by Grampedo 7 · 0 0

A(6,4); B(-2,-2)
distance between A&B=sqrt[(6+2)^2+(4+2)^2]
=sqrt[64+36]
=sqrt(100)
=10 ANS.

2007-09-15 13:38:25 · answer #2 · answered by Anonymous · 0 0

Plot the two on a x,y coordinate system. Then make a right triangle using the two points. You will then get a short side of 6 and a long side of 8. Use the Pythagorean therom and you get the length of the hypotenuse of the triangle and that is your distance. a^2 +b^2 = c^2 final answer is 10.

2007-09-15 13:32:47 · answer #3 · answered by Rochesmk 1 · 1 0

10

2007-09-15 13:32:19 · answer #4 · answered by nishjain7 3 · 0 1

d = sqrt((-2-6)^2 +(-2-4)^2)
d= sqrt(64+36)
d=10

2007-09-15 13:33:16 · answer #5 · answered by ironduke8159 7 · 0 0

root over of the summation of squares of the difference of x-coordinate and y-co ordinate.....
that means __________________
\/ {6-(-2)}^2 + {4-(-2)}^2
_________
= \/ 8^2 + 6^2
= 10

2007-09-15 13:34:46 · answer #6 · answered by abhisikta_tinni 1 · 0 0

the distance from (a,b) to (c,d) is
sqrt((a-c)^2+(b-d)^2))

2007-09-15 13:33:39 · answer #7 · answered by Theta40 7 · 0 0

u have to use the distnce formula....

d=square root of (x2- x1)squared + (y2-y1)squared

2007-09-15 13:35:17 · answer #8 · answered by Anonymous · 0 0

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