This is an application of the Pythagorean Theorem.
If you plot these 2 points on graph paper, you will see that the horizontal distance is 6 units. The vertical distance is also 6 units. The hypotenuse is therefore
sq.rt.(6^2+6^2), =sq.rt(72), =6rt2
Mathematically, the formula is
d^2 =[y(2)-y(1)]^2 +[x(2)-x(1)]^2
d, of course, is obtained by taking the sq.rt. of both sides.
2007-09-15 06:38:09
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answer #1
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answered by Grampedo 7
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A(6,4); B(-2,-2)
distance between A&B=sqrt[(6+2)^2+(4+2)^2]
=sqrt[64+36]
=sqrt(100)
=10 ANS.
2007-09-15 13:38:25
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answer #2
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answered by Anonymous
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Plot the two on a x,y coordinate system. Then make a right triangle using the two points. You will then get a short side of 6 and a long side of 8. Use the Pythagorean therom and you get the length of the hypotenuse of the triangle and that is your distance. a^2 +b^2 = c^2 final answer is 10.
2007-09-15 13:32:47
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answer #3
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answered by Rochesmk 1
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10
2007-09-15 13:32:19
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answer #4
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answered by nishjain7 3
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d = sqrt((-2-6)^2 +(-2-4)^2)
d= sqrt(64+36)
d=10
2007-09-15 13:33:16
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answer #5
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answered by ironduke8159 7
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root over of the summation of squares of the difference of x-coordinate and y-co ordinate.....
that means __________________
\/ {6-(-2)}^2 + {4-(-2)}^2
_________
= \/ 8^2 + 6^2
= 10
2007-09-15 13:34:46
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answer #6
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answered by abhisikta_tinni 1
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the distance from (a,b) to (c,d) is
sqrt((a-c)^2+(b-d)^2))
2007-09-15 13:33:39
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answer #7
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answered by Theta40 7
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u have to use the distnce formula....
d=square root of (x2- x1)squared + (y2-y1)squared
2007-09-15 13:35:17
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answer #8
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answered by Anonymous
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