find the slope and the y intercept of the line determined by the equation which is -2(x+3y)=5 please no negative remarks, all of your help will be greatly appreciated.
2007-09-15 05:03:55 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
-2(x+3y)=5
You want to get y on the left side.
-2(x+3y)=5
x + 3y = -10
3y = -x -10
y = (-1/3)x - (10/3)
There it is =)
2007-09-15 05:08:53 · answer #1 · answered by Anonymous · 0⤊ 0⤋
-2(x+3y)=5
distribute 2:
-2x - 6y = 5
transpose -2x:
-6y = 2x + 5
divide both sides by -6:
y = (-2/6)x + (-5/6)
y = (-1/3)x + (-5/6)
The equation is now in the slope intercept form y =mx + b, where the slope is (-1/3) and the y-intercept is (-5/6).
2007-09-15 12:10:17 · answer #2 · answered by tangy 5 · 0⤊ 0⤋
-2(x + 3y) = 5
-2x - 6y = 5
6y = -2x - 5
divide by 6
y = (-2/6) x - 5/6
y = -1/3(x) - 5/6
comparing with standard form, y = mx + c, where m = slope and c = intercept
slope of the given line = -1/3 and y intercept = -5/6
2007-09-15 12:12:56 · answer #3 · answered by mohanrao d 7 · 0⤊ 0⤋
x + 3y = -5/2
3y = -x - 5/2
y = -x/3 - 5/6
slope = -3
intercept = -5/6
when x = 0 y = -5/6
2007-09-15 12:12:17 · answer #4 · answered by Beardo 7 · 0⤊ 0⤋