1) A class of 27 pupils was divided equally into 3 groups, A,B & C. A box of marbles was shared among the?

Question

pupils so that group A had twice the number of marbles Group B had. Each pupil in Group B had 4 marbles more than each pupil in Group C. If the pupils in Group C received a total of 549 marbles, how many marbles were shared out ?

Answer 1

Each group had 9 pupils
Group C received a total of 549 marbles
Therefore each of them recd.549/9 or 61 marbles
Each pupil in Group B recd 4 marbles more than each student of Group c recd
Therefore each pupil of group B recd 61+4 or 65 marbles
Total marbles revd by group B
=65*9=585
And Group A recd 585*2 or 1170 marbles
Therefore,the total no of marbles recd by all the pupils
=549+585+1170=2304

Answer 2

Group A: 9 x 130 = 1170

Group B: 9 X 65 = 585

Group C: 9 x 61 = 549
-------
2304 marbles

Answer 3

let the marbles of each one in group C = x
total marbles in group C = 9x
marbles of each person in group B = x + 4
total marbles in group B = 9(x + 4)
marbles of group A = 18(x + 4)
9x = 549
x = 61
marbles in group B = 9(61 + 4) = 9(65)
= 585
marbles of group A = 2* 585 = 1170
So total = 549 + 585 + 1170 = 2304

Answer 4

Group C: 549 total divided by 9 students = 61 each
Group B = 65 each x 9 students = 585
Group A = twice group B = 1170

Grand total = 2304

Answer 5

27 / 3 = 9
549 / 9 = 61
61 +4 = 65 * 9 = 585
585 * 2 = 1170
1170 + 585 + 549 = 2304

Answer 6

the smallest number of marbles he could have is 58 this is easiest determined by adding 4 to 6 to get 10 and then increasing by 6's 10,16,22,28... then go through with 5's and see who's 3 above 5 and run down the line etc btw24+2 is 26, not 28 ;)

Answer 7

9 in each group

C - 549 in total, so 549/9 = 61 each
so B - 65 each or 65 x 9 = 585 in total
A - 1,170

Total - 1,170 + 585 + 549 = 2,304

Answer 8

Marbles which are shared out by group A,B,C are 1170,585,549 respectively.

Answer 9

2170 marble were shared out

Answer 10

2322.