Integration help?

0 ⤊

Integrate 1/(cos2x - 1)

Thanks in advance =)

2007-09-15 03:29:06 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

cos2x - 1
= cos²x - sin²x - 1
= 1 - sin²x - sin²x - 1
= -2sin²x

1/(-2sin²x)
= (-½)csc²x

Integrate this to get ½cot(x) + c

2007-09-15 03:39:32 · answer #1 · answered by gudspeling 7 · 0⤊ 0⤋

cotg(x)/2

cos 2x = (cosx )^2-(sinx)^2 and 1 = (cosx )^2+(sinx)^2

so integration is -1/(sinx)^2

2007-09-15 10:42:44 · answer #2 · answered by maussy 7 · 0⤊ 1⤋