Silver iodide powder has been used as an antiseptic and as an agent to seed clouds for rain. Silver oxidide is 45.9% silver by mass. If u seperate a 50-g sample of silver iodide into its element,silver and iodine, how much silver would u have?
2007-09-15 03:01:10 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
the above answers are very perfect and thats the way you should calculate the amount of Ag in the given AgI sample.
But, there's a shortcut. Its a 2 component system (it has only Ag and I) So, if 45.9% of Ag is present in AgI by mass, rest will be I (54.1%)
so, 45.9%(50g) = 45.9 X 50/100 = 22.95g of Ag
which is very straight forward answer. (it is useful for multiple choice answer system, if u r teacher asks u show the method u follow, u cant show this)
Will this help?
Hve fun with Chemisrty
2007-09-15 03:28:54 · answer #1 · answered by murthy 3 · 0⤊ 0⤋
Since silver oxide would contain a lot more silver than that, plus the facts that there is no such thing as "silver oxidide" and you were talking about silver iodide, we can go with that, although you don't even need to know that to solve this math question disguised as a chemistry problem. To calculate 45.9% of 50 g, you multiply 0.459 by 50 and round to 2 significant figures.
If you want to know how many moles of silver this is, then it becomes a chemistry problem, and you divide by the atomic weight.
2007-09-15 03:19:20 · answer #2 · answered by Anonymous · 0⤊ 0⤋
AgI mass molar is 108+127 =235
Fractional mass of Ag = 108/(108+127) = 108/235 =0.459
so in 50g mass of Ag = 50*0.459 = 22.98 g of Ag (Ag =silver)
2007-09-15 03:16:47 · answer #3 · answered by maussy 7 · 0⤊ 0⤋
u would have 22.976 g of silver from the 50 g sample of silver iodide coz first u get the moles of AgI then you get the moles of Ag then the grams of Ag
***ella k b****
2007-09-15 03:21:26 · answer #4 · answered by miaka y 2 · 0⤊ 0⤋