Since Bill Belichick just got caught cheating be stealing signals from other head coaches, should he have an asterisk by his name?
2007-09-14 21:27:00 · 10 answers · asked by Anonymous in Sports ➔ Football (American)
Yes. His "success" has been tarnished by this discovery of cheating. The "genius" is perhaps just another coach who found out cheating pays off. Belicheat deserved a much harsher penalty from the NFL like a suspension without pay for 1-2 years for winning with cheating in this manner. How many wins came as a direct result of this cheating?
2007-09-15 02:09:23 · answer #1 · answered by perdidobums 5 · 0⤊ 2⤋
No, every coach does it and bill was just unlucky enough to get caught. If you do that every team, coach and player would have a * next to their name for cheating in someway.
2007-09-15 10:58:14 · answer #2 · answered by :) 3 · 0⤊ 0⤋
Only if an employee comes out to claim he cheated in those superbowls, where each was decided by 3 points or less.
2007-09-15 06:02:37 · answer #3 · answered by Billy Dee 7 · 0⤊ 0⤋
how does Bonnie know he didnt win fairly? the camera was confescated befor 1/2 time ? all teans do it..most players in the NFL take roids........everyone is gunning for the Pats because they are jealouse.
2007-09-15 06:02:49 · answer #4 · answered by Anonymous · 2⤊ 0⤋
Big time but I don’t have a problem with it.
Each team should be ready and prepared for anything on Sunday.
2007-09-15 06:49:05 · answer #5 · answered by Bucsfan 5 · 0⤊ 0⤋
If that's the case all the players who take steroids should get one to.
2007-09-15 04:38:28 · answer #6 · answered by Super 5 · 1⤊ 0⤋
Not an asterisk, just a big turd.
2007-09-15 11:11:18 · answer #7 · answered by stan l 7 · 0⤊ 0⤋
I think that might be overdoing it. He is already getting penalized steeply.
2007-09-15 04:43:32 · answer #8 · answered by Anonymous · 0⤊ 1⤋
Yes. He did not win fairly.
2007-09-15 05:51:18 · answer #9 · answered by Anonymous · 0⤊ 2⤋
How do you know how long he has done this for?
2007-09-15 06:10:07 · answer #10 · answered by Red Sawx ® 6 · 0⤊ 0⤋