workdone by magnetic field on a positive charge?

Question

Can anybody tell me what will be the workdone by magnetic field on a positive charge particle?

Answer 1

Work done is defined as the product of the force and the displacement of the particle in the direction of the force.
Thus, Work done = Fs cos(angle between force and displacement)
For magnetic fields, the force acting on the charge will always be at right angles to the motion of the charge. Moving charges are commonly known as Current. From Fleming's Left hand rule, we know that the magnetic force on a charge is always perpendicular to the direction of motion of the charge. Hence, angle between force n displacement = 90
Substituting,
Work done = F s cos (90) = OJ

Answer 2

Zero, Always zero! A pure magnetic field can not change kinetic energy of the charged particle because, the force due to the magnetic field is always perpendicular to the velocity, thus the amount of work done by static magnetic force is always zero. The magnetic field can only change the direction of velocity!

Answer 3

well sweetie, I think is Zero, always zero! A pure magnetic field can not change kinetic energy of the charged particle because, the force due to the magnetic field is always perpendicular to the velocity, thus the amount of work done by static magnetic force is always zero. The magnetic field can only change the direction of velocity. I hope this helps . good question . have awnderful weekend . -B-

Answer 4

some solid solutions right here between some obtuse or maybe incorrect ones. particular to the superb wording of the question: the electrical powered container is going out from the charge, and would not loop returned upon itself. on an analogous time as the magnetic container itself is created by ability of shifting electric charge (yet no longer the static electric container created by ability of a table sure charge!), and continuously loops returned upon itself. This latter property is represented as one among Maxwell's/Heavisides' Equations. The equation in question states that the divergence of a magnetic container is comparable to 0. This describes our cutting-edge understand-how that the magnetic container or strains do no longer originate from a element charge, unlike an electric container. And that, returned, the magnetic container itself has no line ends, because of the fact the strains (or container) continuously varieties a non-end loop returned upon itself.

Answer 5

The Lorentz force experienced by a charged particle moving in a magnetic field is ;
F = Bqvsinθ ; B,v-vectors, q -scalar
=q(vXB)

Workdone = F.l (Both vectors)=Flcosθ
l -vector distance travelled

Answer 6

magnetic field never does work because magnetic force is perpendicular to velocity

Answer 7

It will be the vector product (the inner product) of the amount amount of force exerted on the particle times the direction through which the particle moves. If neither of them are constant (which they usually aren't) then it will be the integral of the instantaneous forces and directions.
In either event, it will be measured in Joules.

HTH

Doug