What are the differences between the two transmitting wires and the two receiving wires?
2007-09-14 15:29:47 · 5 answers · asked by charles m 1 in Computers & Internet ➔ Computer Networking
Well for both you have a Plus side and a Minus side.
TX+/TX- RX+/RX- Polarity DOES matter mainly for bandwidth but also because that is the STANDARD set with ethernet.
So one of the wires in each pair is positive, and one is negative.
These pairs use a kind of transmission that is immune to noise. How this works is that the signal is interpretted as the relative difference between the wires in the pair. If there is an external signal that interferes with the wires, it will affect both wires in the pair, so if the signal is the relative difference between the wires in the pair you still can discern the correct signal.
That is about as simple as I have seen it explained.
2007-09-15 01:09:32 · answer #1 · answered by Tracy L 7 · 0⤊ 0⤋
Well, that's easy enough: the transmitting wires are for transmitting, the receiving wires are for receiving data. :)
Apart from that: back in the old days some companies drew up a standard for ethernet cabling. And this is what they came up with. Their intention (at the time) was that the remaining four wires could be used whenever needed (or required) if speeds would go up.
2007-09-14 15:34:29 · answer #2 · answered by pete_can_do 5 · 0⤊ 0⤋
Everyone give colors, but not what "standard" they follow (T568A or T568B). Green/green white is one pair, and Orange/orange white is the other pair. One standard uses one on pins 1-2, the other standard uses the other pair on pins 1-2. The real answer is wires on pins 1-2 are the TX pair, wires on pins 3 and 6 are the RX pair, regardless of colors... That is all you need to know... So, check the TX pair on your PC side., the RX pair on the other end, one of those is bad.
2016-05-19 22:59:24 · answer #3 · answered by ? 3 · 0⤊ 0⤋
The Tx side requires a TWISTED PAIR to get the speeds we need.
Same with the Rx side....
2007-09-14 15:37:21 · answer #4 · answered by Anonymous · 0⤊ 0⤋
series and parallel
2007-09-14 15:33:24 · answer #5 · answered by JavaScript_Junkie 6 · 0⤊ 1⤋