A quarterback claims that he can throw the football a horizontal distance of 176 m. Furthermore, he claims that he can do this by launching the ball at the relatively low angle of 25.4 ° above the horizontal. To evaluate this claim, determine the speed with which this quarterback must throw the ball. Assume that the ball is launched and caught at the same vertical level and that air resistance can be ignored. For comparison a baseball pitcher who can accurately throw a fastball at 45 m/s (100 mph) would be considered exceptional.
2007-09-14 14:36:04 · 4 answers · asked by lonelygirlinhell 1 in Science & Mathematics ➔ Physics
x-xo=vo cos(25.4)t =176 horizontal
y-yo= vo sin(25.4)t -1/2gt^2 =0 vertical
eliminate t and find vo
estimate the relative mass of baseball and football and max speed should vary with ratio. because the force behind a throw is d(mv)/dt = F =force of the players throwing arm
2007-09-14 14:56:10 · answer #1 · answered by meg 7 · 0⤊ 0⤋
The equation of the trejectory can be described as
y= bx -cx^2 where b = tan (angle-0)
& c = g/2(v-0 cos(angle-0) . 0 means initial start parameter.
g = gravity accelaration = 9.756m/sec^2
When the ball hit the ground, y- final = 0.
so x(b-cx) = 0 It has two roots 0 (represents the initial distance) and the x final = b/c = 176 meters.
c= b/176 = tan 24.5/176 = 0.4972/176 = ..002825
Substituting the values for g and cos 24.5 =.8954,
9.76/2(v-0. 0.8954)^2 = 0.002825.
v-0 ^2 = 2154.5 or The initial velocity v-0 = 46.4 m/ sec.
If you take into account the height of the player- say about 6 ft,
Then the v-0 will be right about 45m/sec or less.
2007-09-14 22:34:12 · answer #2 · answered by stvenryn 4 · 0⤊ 0⤋
No one on this site is physic.
2007-09-14 21:42:24 · answer #3 · answered by Anonymous · 0⤊ 2⤋
whatever...
2007-09-14 21:39:45 · answer #4 · answered by dixie_chick 2 · 0⤊ 1⤋