How many milliliters of 3.0 M H2SO4 are required to react with 0.80 g of CuO?

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How many milliliters of 3.0 M H2SO4 are required to react with 0.80 g of CuO?

I'm kinda new to the whole Yahoo Ask thing, but I'd gladly appreciate anyone who can help me with this question. And if at all possible, I would like to know how get started with it please.

Oh and H2SO4 is sulfuric acid

2007-09-14 14:16:23 · 2 answers · asked by j0shua0h 1 in Science & Mathematics ➔ Chemistry

2 answers

H2SO4 + CuO = CuSO4 + H2O
So Molar ratios are 1:1::1:1
Mr(CuO) = 64 + 16 = 80
Moles (CuO) = 0.80/80 = 0.01 moles
As the molar ratios are 1:1 we need 0.01 moles of H2SO4
vol(H2SO4) = moles x 1000/[conc]
vol(H2SO4) = 0.01 x 1000/3.0 = 3.333...cm^3

2007-09-22 10:16:11 · answer #1 · answered by lenpol7 7 · 0⤊ 0⤋

3 ml

2007-09-14 14:31:18 · answer #2 · answered by Ioannis I 1 · 0⤊ 1⤋