What three techniques can be used to solve a quadratic equation? Demonstrate these techniques on the equation "12x2 - 10x - 42 = 0."
I already did completing the square
Thanks everybody
2007-09-14 13:46:34 · 6 answers · asked by crackr 3 in Science & Mathematics ➔ Mathematics
Factor:
12x2 - 10x - 42 = 0
2(3x-7)(2x+3) =0
x = 7/3 and x= -3/2
Quadratic formula:
x = [-b +/- sqrt(b^2-4ac)]/(2a) where a = 12, b = -10 and
c = -42. Just plug the numbers in and simplify.
You already completed the square so no need to repeat it here.
2007-09-14 14:02:59 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
and factoring (4x+6)(3x-7)
4x=6 and 3x =7
x=6/4 and x=7/3
x=3/2 and x=7/3
and quadratic formula -b +or- [sq. root of b^2 -4ac] ; then take the answer and dive it by 2a
a = 12 b = -10 c = 42
2007-09-14 13:51:51 · answer #2 · answered by batman is a terrible superhero 1 · 0⤊ 0⤋
Use the quadratic formula, sorry I can't paste the equation but you can google it.
2007-09-14 13:53:08 · answer #3 · answered by Mojitabean 4 · 0⤊ 0⤋
quadratic equation....where x= [- b +/- sqrt(b^2-(4ac))] / (2a)
2007-09-14 13:54:32 · answer #4 · answered by mrsbrainiac314 3 · 0⤊ 0⤋
factorisation
formula
2007-09-14 13:52:13 · answer #5 · answered by Osama Bin Lorry 3 · 0⤊ 0⤋
doodi
2007-09-14 13:50:44 · answer #6 · answered by Anonymous · 0⤊ 1⤋