What is the domain of k (s) = sqrt -2-s? Please help?

Answer 1

k (s) = sqrt( -2-s)
If s is positive then we have a negative square root.
If s = -2, then k(s) = 0
If s<-2, then we have a positive square root
Thus the domain is - infinity < x <= 0 or (-infinity, 0]

Answer 2

k(s) = √(-2-s)
The domain is any value of s such that -2 - s is not negative or that it is greater than or equal to 0
-2 - s ≥ 0
-s ≥ 2
s ≤ -2
The domain as any real number less than or equal to -2
(-∞ , -2]

Answer 3

k(s)=sqrt[-2-s].
domain:

-2-s>/=0
-2>/=s
s