e^(ax) = Ce^(bx), where a is not equal to b. Solve for X. Can someone please help me with this? There are some real smart people on here, so if you are able to answer this question, thanks SOO much. I am in awe of your brilliance.
2007-09-14 10:08:50 · 5 answers · asked by ILuvTaraReid 2 in Science & Mathematics ➔ Mathematics
I need to solve for X.
2007-09-14 10:18:05 · update #1
e^(ax) = Ca^(bx)
C = e^(ax) / a^(bx) = e^(a-b)x
ln C = (a-b)x
x = ln C/(a-b)
2007-09-14 10:19:36 · answer #1 · answered by norman 7 · 1⤊ 0⤋
ax = ln C + bx
ax - bx = ln C
x(a-b) = ln C
x = ln C / (a-b)
2007-09-14 10:17:52 · answer #2 · answered by UnknownD 6 · 3⤊ 0⤋
e^(ax) = Ce^(bx)
lne^ax=lnCe^bx
ax=lnC+bx
(a-b)x=lnC
x=(lnC)/(a-b)
2007-09-14 10:22:44 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I have it wrong
2007-09-14 10:17:08 · answer #4 · answered by 4 · 0⤊ 2⤋
x = ln (c) / (a-b)
2007-09-14 10:21:50 · answer #5 · answered by Xero Sinko 2 · 0⤊ 0⤋