please help me:
1.what is the smallest natural number 54 must be multiplied by so that the result is a perfect square? (hint: write the prime factor of 54 first) show your work.
2.find the smallest natural number that 94 must be multiplied by so that the number created is divisible by 12. Show your work.
3. If the GCF and the LCM of two numbers are 15 and 600 respectively and one of the numbers is 75, find the other number. Show your work.
2007-09-14 09:59:51 · 5 answers · asked by rain+sunshine=rainbow 1 in Science & Mathematics ➔ Mathematics
DYOHW
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2007-09-14 10:10:19 · answer #1 · answered by muddypuppyuk 5 · 0⤊ 0⤋
1. 54 = 3 * 3 * 2 * 3
so I think you need 6 to get to 18 squared
2. 94 = 2 * 47
again you multiply by 6 to get 2 * 47 * 6 = 12 * 47
3. 75 = 15 * 5
600 = 75 * 8
15 * 4 - no - 300 is LCM
15 * 3 = 45 no - not a factor of 600
15 * 6 = 90 no
15 * 8 = 120 LOOKS GOOD
2007-09-14 10:20:51 · answer #2 · answered by Beardo 7 · 0⤊ 1⤋
1.
54=2*3*3*3
54*6=2*3*3*3*2*3=18*18
2.
94=2*47
12=2*6
94*6/12=2*47*6/2/6=47
3.
any two numbers a,b have a*b=GCF*LCM
so if a=75 GCF=15 LCM=600
b=15*600/75=120
2007-09-14 10:15:01 · answer #3 · answered by vIcToR 1 · 0⤊ 1⤋
you have a good sense of making a problem
please do the proper explanation
I still can not get it
54 is not a perfect square
all I know is 6 (9) = 54
6 is also not a perfect square
what do you mean
there is something in your problem
let us know
2007-09-14 10:13:20 · answer #4 · answered by CPUcate 6 · 0⤊ 0⤋
do your own work!
2007-09-14 10:06:55 · answer #5 · answered by bLeSsEd 4 · 1⤊ 0⤋