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3x^2-13x=2x
Please show me how to solve this function numerically and algebraically.

2007-09-14 09:56:30 · 5 answers · asked by w_xsoadx_w 2 in Science & Mathematics Mathematics

5 answers

3x^2-13x=2x ?
3x^2=15x
x^2=5x

x = 0 or 5

numerically - no idea

2007-09-14 10:09:41 · answer #1 · answered by Beardo 7 · 0 2

*Set the equation to "0" >>>

First: combine "like" terms - subtract 2x from both sides (when you move a term to the opposite side, always use the opposite sign).

3x^2-13x-2x = 2x-2x
3x^2-13x-2x = 0
3x^2 - 15x = 0

Sec: factor the expression - the least common factor is 3x.

3x(x - 5) = 0

Third: solve the "x" variables - set both variables to "0"

a. 3x = 0
Divide both sides by 3.
3x/3 = 0/3
x = 0

b. x - 5 = 0
add 5 to both sides.
x - 5+5 = 0+5
x = 5

Solutions: 0, 5

2007-09-14 10:04:49 · answer #2 · answered by ♪♥Annie♥♪ 6 · 2 1

i'm ninety 9.9% helpful that x on that's very own can't be expressed as a functionality of y, that's, you won't be able to have x = f(y). this style of situation demands some thing like an iterative technique, jointly with Newton's technique to remedy for x, the place approximations to x are continuously placed back right into a formulation to acquire greater useful and greater useful approximations.

2016-11-10 11:14:36 · answer #3 · answered by ? 4 · 0 0

3x^2 - 2x - 13 x

3x^2 - 15 x

3x (x - 5)

x = 5

3(5)^2 - 2(5) - 13 (5)

75 - 10 - 65 = 0

0 = 0

trial and error for the numerical solution

2007-09-14 10:03:31 · answer #4 · answered by   4 · 0 2

3x^2-13x=2x now you need to divide everything by x.
3x-13=2 now add 13 to 2
3x=15 now divide each side by 3
x=5

2007-09-14 10:02:45 · answer #5 · answered by ashley 3 · 1 4

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