Maths equation help?

Question

Can you solve the problems below and explain how you did?

1 - 8x^3 x 3y^2 divided by 6x^2 x 4y^3

2 - (6x divided by 18x^2) ^2

Ah, I got the same thing for number 1, I wasn't sure if it was right or not, thankyou

Answer 1

1
8x^3 x 3y^2 divided by 6x^2 x 4y^3

( 8x^3 * 3y^2) / (6x^2 * 4y^3) =

(8x * 3) / (6 * 4y) =

24x / 24 y =

x/y


2

(6x divided by 18x^2) ^2

(6x / 18x^2) ^2 =

(6/18x)^2 =

(1/6x)^2 =

1/(36x^2)

Answer 2

(1) First you look at the 8x^3 and the 6x², 8/6 simplifies to 4/3. then you look at the x^3 over the x², to simplify that expression, you would subtract the exponents. so 3-2=1 so you have an x left over, which goes on the top (numerator) of the fraction.

So at this point we have 4x/3

Next you move on to the 3y² and 4y^3, 3/4 does not simplify so you just leave that the same then you do the same as before by subtracting the exponents. 2-3 which is -1. So you would have y^-1, you can move that to the bottom (denominator) by making the -1 positive.

So now we have (4x * 3)/(3 * 4y).

Now you can multiply 4x * 3 on the numerator which = 12x.
On the denominator you can multiply 3 * 4y which = 12y.

Now we have 12x/12y which you can simplify 12/12 to 1/1 which is just 1 so you have 1*x/y which ultimately =

x/y

(2) When you first start you need to look at what is inside the parenthesis 6x/18x². We can do the same steps that we did on the first one.

simplify 6/18 to 1/3
Then look at the x/x² subtract the exponents (1-2) and you get -1 so x^-1 can be moved to the denominator by making the exponent positive.

So now we have (1/3x)² all you have to do is distribute the ² into each number.

(1²/3²x²) which = (1/9x²)

ANSWERS:
(1) x/y
(2) (1/9x²)

I hope I have explained everything correctly, if I lost you in any of the steps just email me and I will help.

Answer 3

1 - 8x^3 x 3y^2 divided by 6x^2 x 4y^3

8x^3 x 3y^2 / 6x^2 x 4y^3
= 24 x^3y^2 / 24 x^2 y^3
= 24/24 x X^3-2 x Y^2-3
= X^1 x Y^-1
= x/y

2 - (6x divided by 18x^2) ^2

(6x / 18x^2)^2
=(6/18 x X^1-2)^2
= (1/3 x X^-1)^2
= (1/ 3x)^2
= 1/ 9x^2

Answer 4

1 - 8x^3 x 3y^2 divided by 6x^2 x 4y^3
=24x^3y^2/24x^2y^3=x/y
2 - (6x divided by 18x^2) ^2=(1/3x)^2=1/9x^2

Answer 5

As you have written, there is a -ve sign at the start of each question. Or is this meant to be a dash?
I will go with former but you may have other ideas!
Omit the - sign in answer if it is not meant to be in question.

Question 1
( - 24 ) ( x ³ )( y ² )
= -----------------------
( 24 ) ( x ² )(y ³)

= - x / y

Question 2
= - (1 / 3x) ²
= - (1 / 9 x ²)

Answer 6

1. 8x^3x3y^2/6x^2x4y^3
=x/yAN.s.
2.6x/(18x^2)^2
=6x/324x^4
=1/54x^3. ANS.

Answer 7

oh em geee! that isnt our homework is it

i think i may die

can i copy yours

or is that zoes homework

in which case hah! poor girl

serves her right for spending too long on the phone with you

i dont have a clue sorry

not that i really tried xD

but at least ive got 2 points now

xxx

Answer 8

x/y and 1/9x^2

Answer 9

ask me on monday too if you want i still wont know the answer though i failed maths

Answer 10

sorry its friday night and im on the way to being drunk ask me on monday