Find the equation of the line parallel to the graph of 3x-y=5, that contains the points (-1,4)?

Question

the answer is y=3x+7. I need to know how to get the answer. ten points to who can explain it! Thank you!

Answer 1

3x-y=5
=> y = 3x + 5
=> slope = 3 & // slope = 3
=> m = 3 & pt = (-1,4)
& use

Eqt of a line = y – y1 = m ( x – x1 )

etc

Answer 2

Starting with
3x-y=5
Let's rearrange it, by adding y to both sides:
3x = 5 + y
and subtracting 5 from both sides:
3x - 5 = y
or
y = 3x - 5

Now, the number in front of the x is the "slope".
Parallel lines have the same slope, so we need an equation like:
y = 3x + something

That "someting" is actually the intercept -- what you have left whenever x is zero. The intercept is usually shown as "b" (and the slope is usually shown as "m", for reasons I never understood!)

Anyhow, to find the "b" in
y = 3x + b
just plug in the points (-1,4), or x = -1 and y = 4, to get:
4 = 3(-1) + b
or
4 = -3 + b
Just add 3 to both sides, to get:
7 = b

So the slope is 3, the intercept is 7, and the equation is:
y = 3x + 7

Answer 3

*Place the equation in slope-intercept form, which is y = mx+b

First: subtract "3x" from both sides (when you move a term to the opposite side, always use the opposite sign).

3x - 3x - y = 5- 3x
- y = 5 - 3x
- y = - 3x+5

*Rule: "y" has to be positive (change all signs).

y = 3x - 5
*The slope = a whole number/fraction beside the "x" variable, in this case the slope is 3.

Sec: place the slope & point (-1,4) in the point-slope formula, which is y - first y = m(x - first x)

y - 4 = 3(x - (-1))
y - 4 = 3(x + 1)
y - 4 = 3(x)+3(1)
y - 4 = 3x + 3

Third: isolate "y" - add 4 to both sides.

y - 4+4 = 3x + 3+4
y = 3x+7

Answer 4

1) given that 3x-y = 5, then:

y = 3x - 5, so any line parallel to it will have the gradient m = 3.

So the equation of your line will be of the form y = 3x + c.

Now, x = -1 when y = 4, so we substitute these values in

y = 3x + c to find the value of c, so:

4 = -3 + c, so

c = 7, and

y = 3x + 7.

Hope this helps, Twiggy.

Answer 5

certainly 3x-y = 5 is the same as y = 3x -5

how about 3x + 7 = y

y = mx + b is in slope intercept form and m is the slope and it's = to 3

a point is (-1, 4)

so you take your slope which is 3 and go

3 (x+1) = y - 4
3x + 3 = y - 4
3x + 7 = y

Answer 6

any line parallel to the given line may be written as 3x-y=k where k is a constant.this line passes through (-1,4) and so k=-7
so the line is 3x-y+7=0