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Will it be Kennedy, Hughes, or Chamberlain?? They all seem to have a lot of promise in their careers.

2007-09-14 06:07:10 · 10 answers · asked by AbCDZyC 1 in Sports Baseball

Please no sarcastic comments from fans of a team that wins once every 86 years!

2007-09-14 06:19:43 · update #1

10 answers

None of thee above!!

2007-09-14 06:13:29 · answer #1 · answered by Chad K 7 · 0 0

I see great potential for Kennedy and Chamberlain.

Based on this season Chamberlain and Kennedy are going to be the main guys, but I havent lost hope in Hughes.

I believe that Hughes needs a little more developing in the Majors and will turn out to be the best of the three. He wasnt ranked the #1 Prospect AND Pitching Prospect for nothing.

2007-09-14 13:46:49 · answer #2 · answered by #1 New York Yankees Fan 6 · 0 0

It's hard to tell. Kennedy definitely has better stuff than Hughes, so we can eliminate Hughes from the equation.

If Joba becomes a starter, than without a doubt he will be the ace. If he says a set-up man then Kennedy will probably be the next ace.

2007-09-14 13:12:07 · answer #3 · answered by Crusader 5 · 0 0

Joba Chamberlain he has the Most Promise to the Yankees.

2007-09-14 13:18:54 · answer #4 · answered by tfoley5000 7 · 0 0

Wang is only 27 or 28 so I'd think he'd be your ace for the next 5 years at least.

2007-09-14 14:57:28 · answer #5 · answered by red4tribe 6 · 0 0

Kennedy - unless Dontrelle comes over. And if you think Wang is already an ace.

2007-09-14 23:48:56 · answer #6 · answered by Siddhartha Basu 4 · 0 0

Id say Kennedy..

2007-09-14 19:25:08 · answer #7 · answered by Anonymous · 0 0

I'd like to see Joba start next year. He could be you next ace.

2007-09-14 13:26:27 · answer #8 · answered by Oz 7 · 0 0

Hideki Irabu.....wait no....Carl Pavano....wait no....Kei Igawa....wait no.....Jack McDowell....wait no....Kenny Rogers....wait no....Jeff Weaver...

2007-09-14 14:09:53 · answer #9 · answered by J-Far 6 · 1 1

I think it will be Wang

2007-09-14 13:50:07 · answer #10 · answered by cptndaveahoe 6 · 1 0

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