a quaterback throws a football toward a reciever?

Question

a quaterback throws a football towards a reciever with an initial speed of 22m/s, at an angle of 34 degrees above the horizontal. At that instant, the reciever is 21 m from the quarterback. The acceleration of gravity is 9.8 m/s ^2. WIth what constant speed should the reciever run in order to catch the football at the level at which it was thrown? Answer in units of m/s.

Answer 1

The equations for this are
The speed and location of the football
x(t)=22*cos(34)*t
and
vy(t)=22*sin(34)*t-g*t

When vy(t')=0, the football hits apogee, so t' is 1/2 the total flight time of the ball
t'=22*sin(34)/g
so the flight time,
t=44*sin(34)/g

The receiver position is
x(t)=21+vr*t
Since the ball returns to the thrown height at time t, the x(t) for the ball and receiver must be equal
21+vr*t=22*cos(34)*t
since we know t, plug it in and crunch for vr
vr=22*(cos(34)-21/(2*sin(34)/g))

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Answer 2

it is not important. Roy Williams might nonetheless drop it. Ask this in a math or a homework help area. This has no longer something to do with the subject count of 'soccer' different than one is being thrown.