A swimmer dives off a cliff with a running horizontal leap.What must her minimum spped be just as she leaves?

Question

the top of the cliff so that she will miss the ledge at the bottom, which is 1.50m wide and 9.50m below the top of the cliff? And what must the divers initial speed be in milers per hour?

Answer 1

The equations for this are
x(t)=v0*t
and y(t)=-.5*g*t^2

look at y(t)=-9.5 and solve for v0 such that x(t)>1.5

using g=10

t=sqrt(1.9)
1.5 v0>1.5/sqrt(1.9)

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