Let m = Mother's age, f = Father's age
m = f-8 =======> mother is 8 years younger
m = (5/7)f ======> mother's age is 5/7 of father's
Substitute the value for m in the second eqn into the first
f-8 = 5f/7
Multiply both sides by 7
7f - 56 = 5f
Add 56 to each side
7f = 5f + 56
Subtract 5f from each side
2f = 56
Divide each side by 2 to find the father's age
f = 28
Put this value back in the first equation to find mom's age
m = f-8 = 20
When they got married, Patricia's mother was 20 and her father was 28.
:)
2007-09-14 04:37:48
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answer #1
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answered by MamaMia © 7
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Let's make x Patricia's mother. That means Patricia's father would be x+8. So the equation would be:
x/x+8 = 5/7
If you cross multiply:
7x = 5(x+8), or 7x = 5x + 40
Subtract 5x from both sides and you get:
2x = 40
x = 20 (Patricia's mother's age)
and x+8 = 28 (Patricia's father's age)
To check:
Does 20/28 = 5/7? Divide the numerator and the denominator of 20/28 by 4, and you get 5/7.
2007-09-14 11:40:39
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answer #2
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answered by Anonymous
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Age of mother = x
Age of father = y
Patricia's mother is eight years younger than her father
x = y - 8
When they were married, she was 5/7 as old as he
x = (5/7)y
(5/7) y = y - 8
8 = y - (5/7)y
8 = (2/7)y
y = 8(7/2)
y = 28
x = (5/7)(28)
x = 20
Age of mother = 20
Age of father = 28
2007-09-14 11:39:22
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answer #3
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answered by coolesteugene 2
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Let x and y be the ages of Patricia's parents (mother and father resp).
x = y - 8
x = 5y / 7
7x = 5y
7y - 56 = 5y
2y = 56
y = 28
x = y - 8 = 20
They were 20 and 28 respectively when they got married.
2007-09-14 11:39:58
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answer #4
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answered by Swamy 7
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M=F-8
M=(5 divided by 7)multiply F
F-8=(5 divided by 7)multiply F
F-(5 divided by 7)multiply F=8
(2 divided by 7)multiply F=8
F=8 multiply 7 divide by 2
=28
M=F-8
=28-8=20
2007-09-14 11:42:40
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answer #5
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answered by Ricky 2
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mom was 20 and dad was 28
mom = x, dad = x + 8
5/7(x+ 8) = x, and solve
after I distributed and got rid of the fraction I got
5x + 40 = 7x, so x = 20
2007-09-14 11:45:44
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answer #6
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answered by sfroggy5 6
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x = mother's age
y = father's age
y = x + 8
5/7y = x
y = 7/5x
7/5x = x + 8
2/5x = 8
x = 20
The mother was 20 years old.
y = x +8 = 20 + 8 = 28
The father was 28 years old.
2007-09-14 11:41:17
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answer #7
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answered by Chameleon 2
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