A golf ball is hit at a speed of 12 m/s at an angle of 30 degrees above the horizontal.?

Question

Find: (a) the time before it hits the ground; (b) the range; and (c) the maximum height that it reaches during its flight.

Answer 1

Time =(2Usin30)/g
=(2*12sin 30)/10
=(24*0.5)/10
=1.2secs

Range=(u^2cos60)/10
=(144*0.5)/10
=7.2m

Height=(u^2sin30)/20
=(144*0.5)/20
=3.6m

Answer 2

b) The distance is
12*cos(30)*t
where t is the total flight time

a) The total flight time is related to t' as 2*t' where
0=12*sin(30)-g*t'
t=24*sin(30)/g

c) The max height is
y(t')=12*sin(30)*t'-.5*g*t'^2
y(t')=72*sin(30)^2/g

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