What volume of a liquid having a density of 6.44 g/cm3 is needed to supply 9.00 grams of that liquid? Answer in cm3. I've tried to just plug in the known values to D=M/V and I'm not getting the right answer but I was told by a TA that by manipulating D=M/V to V=D/M I could get the answer. What I get is 6.44g/cm^3 / 9.00g, which comes out to .715555556 which with sif figs comes to .716 after rounding. Any thoughts?
2007-09-14 03:35:04 · 2 answers · asked by steelhead3686 3 in Science & Mathematics ➔ Chemistry
Density=mass/volume
Now, yr job is to find the volume, thus
Volume=mass/density
Given mass=9g,density=6.44g/cm3
volume=9/6.44
=9/6.44
=1.3975cm3
approximately 1.40cm3(3sf)
2007-09-14 03:56:21 · answer #1 · answered by Anonymous · 0⤊ 0⤋
9.00/6.44=1.3975cm^3
2007-09-14 03:38:27 · answer #2 · answered by maussy 7 · 0⤊ 0⤋