I'm sorry.....
I'm really stupid in math so please help me with this math problem!
You have an equal number of nickels, dimes, and quarters with a total value of $6.00. How many of each coin do you have?
a. 3
b. 10
c. 15
d. Not Here
2007-09-14 02:22:15 · 6 answers · asked by WoWzErZ 1 in Science & Mathematics ➔ Mathematics
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2007-09-14 02:28:22 · update #1
First, convert coins to dollars:
1 quarter = 25/100 = 0.25 $
1 dime = 10/100 = 0.10 $
1 nickel = 5/100 = 0.05 $.
Assume that you have an x number of each coin and translate this into the following equation:
0.25x + 0.10x + 0.05x = 6.00 -->
0.40 x = 6.00 --> x = 6.00/0.40 --> x = 15
Therefore, correct answer is (c).
2007-09-14 02:26:55 · answer #1 · answered by Anthony P - Greece 2 · 0⤊ 0⤋
If we have x nickels, x dimes and x quarters, we have :
5x + 10x + 25x = 600
40x = 600
then x = 600/40 = 15 coins of each.
2007-09-14 02:30:59 · answer #2 · answered by Nestor 5 · 0⤊ 0⤋
c. 15
To find the answer
Add the value of the nickel, dime and quarter - that would make a set of coins
5+10+25 = 40 cents
Than divide 6$ to 40 cents = 15
So you have 15 sets of 3 coins.
2007-09-14 02:29:35 · answer #3 · answered by collinss_69 2 · 1⤊ 0⤋
add total value of coins
ie 25+5+10 (I am british and u talk foreign)
40
this into 600 (600 cents that i know=$6)
=15
2007-09-14 02:32:43 · answer #4 · answered by GOLD-FLAW 2 · 0⤊ 0⤋
c. 15
nickels-15*.05=.75
dimes-15*.10=1.50
quarters-15*.25=3.75
+ .75
1.50
3.75
________
= 6.00
2007-09-14 02:26:09 · answer #5 · answered by fuzzbuzz 2 · 0⤊ 0⤋
the answer is c, 15.
2007-09-14 02:31:31 · answer #6 · answered by cutevegetarian 2 · 0⤊ 0⤋