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How many grams of Bromine are in 3.5x10^9 g of seawater which contains 65 ppm by mass Bromine


I need help figuring out how to do the problem. if you show me the work I will reward you the points

2007-09-14 01:03:32 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

65 ppm = 65 mg/kilogram = 0.065 g bromine/g water. Just multiply this factor by the mass of seawater, and you've got it.

2007-09-14 01:31:00 · answer #1 · answered by hcbiochem 7 · 0 0

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