If a body is thown upward, its gravitational acceleration becomes "-"9.8m/s.If a body is dawn nearer to the centre of earth, what will be its gravitational acceleration?e.g. if a pit is dug in to earth and the body is thrown in to it. Explain.
2007-09-13 22:26:50 · 9 answers · asked by Princess 3 in Science & Mathematics ➔ Physics
If you could dig a pit tothe center of the Earth, the gravitational acceleration there wuld be zero. As an object falls into this pit, it still experiences gravitational attraction, but now more and more of the mass of the Earth is 'above' it and is attracting it in an upwards direction.
Doug
2007-09-13 22:32:24 · answer #1 · answered by doug_donaghue 7 · 2⤊ 0⤋
The value of gravitational acceleration decreases on going above the surface of the earth or on going inside the surface of the earth. the acceleration due to gravity is maximum on the surface of the earth.
The formula g = GM/R^2 where g is the gravitational acceleration is not applicable at any point inside or outside the surface of the earth.
U will learn in higher classes that the formula to calculate gravitational acceleration when the body is above the surface is g(r / r + h )^2 where g is the acceleration due to gravity experienced on the surface (i.e. 9.8 m/s^2), r is the radius of the earth and h is the height from the surface of the earth. As the denominator r + h is greater than the numerator r then r/r+h would be less than 1 and so will be (r/r+h)^2. which when multiplied by g will make the answer less than 9.8.
(u can take some values and try it out)
similarly when the body is kept inside the earth surface at a depth 'h', the experienced gravitational force is given by the formula g(1 - h/r). here 1 and h/r are two different terms. g is the gravitational force experienced when the body is at the surface (i.e. 9.8 m/s^2).
So it is like this
2007-09-13 22:51:38 · answer #2 · answered by keep smiling 2 · 1⤊ 0⤋
gravitational acceleration is the acceleration towards the earth that acts on every adn any body. this acceleration acts towards the centre of the earth independent of which direction the body is moving. As u said "If a body is thown upward, its gravitational acceleration becomes "-"9.8m/s." because u considered upwards as positive, the gravitaional acceleration that acts on the body is always towards the centre of the earth, so its -9.8m/s^2
the value of 9.8m/s^2 is an approximate near the surface of the earth but g depends on how far away frm the centre of the earth u are, the closer u are to the centre the larger ur value of g, the further u are the lesser it is. at the centre it is zero
2007-09-13 22:53:53 · answer #3 · answered by chryses 1 · 1⤊ 0⤋
If you dig a pit in earth, the gravity doesn't increase since the mass of the earth above the bottom of the pit is now excluded. Otherwise, you will end up with infintely large gravitational force at the center of the earth.
The equation F = G.m.M / r^2 applies to two masses whose mass is effectively concentrated at their centres of gravity. In that equation if r is reduced F is increased. That just means that g increases as you come nearer to earth (from far off in space) and at the surface of the earth it is 9.8 m/sec^2 .
At the equator, the value of g is slightly less than that at poles since the radius of earth is slightly more at the equator than at the poles.
2007-09-13 22:37:57 · answer #4 · answered by Swamy 7 · 1⤊ 0⤋
If you were in the center of the earth, you would feel no gravitational pull from earth since the mass is equally surrounding you. Though the gravity from the sun and other surrounding bodies would still exert a force on you.
2007-09-13 22:34:04 · answer #5 · answered by John L 2 · 0⤊ 1⤋
The value of gravitational acceleration, 'g' is maximum on the surface of the earth. It reduces as we go to higher altitudes. Also, it reduces as we go below the surface of earth and becomes zero at its centre. It also increases with latitude and becomes maximum at the poles.
2007-09-13 23:17:42 · answer #6 · answered by Madhukar 7 · 1⤊ 0⤋
gravitational acceleration I think should increase as you get closer to the center of the earth. It's actually 9.8 m/s^2.
2007-09-13 22:30:26 · answer #7 · answered by CT 3 · 1⤊ 1⤋
the gravitational acceleration is highest on the land.so when te body is thrown in pit the g. accelleration will be less than +9.8m/s2. but it will be "+"
2007-09-13 23:57:09 · answer #8 · answered by piyaa 2 · 1⤊ 0⤋
this is your elementary physics subject, you will see alot of them D = one million/2 aT^2 D= 0.9 m T= 0.sixty 8 s T^2= 0.4624 0.ninety m = one million/2 a x 0.4624s^2 one million.eighty m= a x 0.04624 s^2 one million.eighty/0.4624 m/s^2 =a a = 3.89 27 m/s^2 rfile purely 2 substantial figures leaving a = 3.9 m/s^2
2016-10-04 13:25:32 · answer #9 · answered by ? 4 · 0⤊ 0⤋