2007-09-13 21:57:27 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Trig identity:
cos(A-B) = cos(A)cos(B) + sin(A)sin(B).
In your case, A=x, B=5, therefore:
cos(x-5) = cos(x)cos(5) + sin(x)sin(5).
Hope this helps :-)
2007-09-13 22:12:23 · answer #1 · answered by Anthony P - Greece 2 · 1⤊ 0⤋
cos x cos 5 + sin x sin 5
You don`t say if it is 5° or 5 radians.
2007-09-14 12:01:23 · answer #2 · answered by Como 7 · 2⤊ 0⤋
Applying the formula: cos(A - B) = cosAcosB + sinAsinB,
cos(x - 5) = cos(x)cos(5) + sin(x)sin(5)
2007-09-14 05:15:53 · answer #3 · answered by MH 1 · 0⤊ 1⤋
cosx cos5+sinxsin5
but it may also be expanded as cos (x-5)=1-(x-5)^2/2!+(x-5)^4/4!-(x-5)^6/6!........upto infinity.
provided x-5 is in radian
2007-09-14 13:55:38 · answer #4 · answered by soumyo 4 · 0⤊ 2⤋
cos(a-b)=cos(a)cos(b)-sin(a)sin(b).
Doug
2007-09-14 05:09:03 · answer #5 · answered by doug_donaghue 7 · 0⤊ 1⤋