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y=2x-2
5x-3y=3

and

y=2x+7
2x+7y=1

PLS. EXPLAIN HOW U FOUND ANSERS, 10 POINTS!!! :) THANKS!

2007-09-13 19:15:07 · 11 answers · asked by chris b 1 in Science & Mathematics Mathematics

11 answers

y=2x-2
5x-3y=3

Substitute:
5x-3(2x-2)=3
5x-6x+6=3
-x+6=3
-x=-3
x=3

y=2x-2
y=2(3)-2
y=4


y=2x+7
2x+7y=1

Substitute again:

2x+7y=1
2x+7(2x+7)=1
2x+14x+49=1
16x+49=1
16x=-48
x=-3

y=2x+7
y=2(-3)+7
y=1



I hope that helped:)

2007-09-13 19:24:27 · answer #1 · answered by Jen 3 · 1 3

Paul was not really criticizing people for just not working - but, rather, for not working AND "sponging" off the church for their food. The verses before and the verse following, 2 Thes 3:11, give the context. Paul recognized that 1) laziness is not a fruit of godliness. (Plenty of scriptures in Proverbs about "sluggards" he would have been familar with!) And 2) if at all possible, one should not be a burden to church. He counseled the same way about widows in the church to Timothy (1 timothy 4): Let those who have the means or who have the family not be a burden on the church. Then the church can care the widows who are truly alone. Paul set the example by working hard, never burdening the church with his needs. Many people today are busier and more productive in retirement than they are before retirement! Any many who are wealthy use their time in productive ways - although they do not hold a traditional job. One minister told me that "there is no retirement plan in God's government". In other words, we can and should ALWAYS be busy doing the Lord's work. But that does not mean always holding a traditional job, etc. But, again, Paul's real focus was unburdening the church from its busybodies and lazy bone sluggards who expected the church to supply their daily bread. god bless

2016-05-19 01:41:52 · answer #2 · answered by Anonymous · 0 0

Question 1
5x - 3(2x - 2) = 3
5x - 6x + 6 = 3
- x + 6 = 3
- x = - 3
x = 3
y = 4

Question 2
2x + 7(2x + 7) = 1
2x + 14x + 49 = 1
16x = - 48
x = - 3
y = 1

2007-09-14 06:08:57 · answer #3 · answered by Como 7 · 4 1

1. First: substitute "2x-2" with "y" in the 2nd equation.

5x - 3(2x-2) = 3
5x - 3(2x)-3(-2) = 3
5x - 6x+6 = 3
- x+6 = 3

Sec: isolate "x" - subtract 6 from both sides (when you move a term to the opposite side, always use the opposite sign).

- x+6-6 = 3-6
- x = - 3

*Rule - the variable x (and y) can't be negative - change all signs > x = 3

Third: substitute 3 with "x" in the 1st equation.

y = 2(3) - 2
y = 6 - 2
y = 4 >>> (3, 4)

*Follow the method to solve the 2nd problem.

2007-09-14 05:19:15 · answer #4 · answered by ♪♥Annie♥♪ 6 · 2 3

Substitute y.
5x-3(2x-2)=3
5x-6x+6=3
-x= -9
x=9
Substitute x.
y=2(9)-2
y=18-2
y=16

2x+7y=1
2x+7(2x+7)=1
2x+14x+49=1
16x= -48
x= -3

y=2x+7
y=2(-3)+7
y= -6+7
y=1
Hope it helps!

2007-09-13 19:24:47 · answer #5 · answered by Anonymous · 1 5

X=3
Y=4
plug y=2x-2 into the equation, 5x-3y=3
5x-3(2x-2)=3
then solve it , you get x=3 . plug that number into y=2x-2
y=2(3)-2
same for the second question.

the second question,
X= -3
Y=1

2007-09-13 19:29:37 · answer #6 · answered by Anonymous · 1 4

in your first example, take the value for y as given in the first equation, y = 2x -2, and substitute that into the second equation thusly:

5x - 3(2x-2) =3

clear parentheses and combine like terms to get:

-x + 6 = 3 and thus x =3

since y =2x-2, y = 4

in the second problem do likewise.

2007-09-13 19:21:21 · answer #7 · answered by VampireDog 6 · 1 5

1)

substitute the y=2x-2 into 5x-3y=3

5x-3(2x-2)=3
5x-6x-6=3
-x=9
x=-9

2) again

2x+7(2x+7)=1
2x+14x+49=1
16x=-48
x=-3

2007-09-13 19:22:46 · answer #8 · answered by Jay 4 · 1 5

y=2x-2...(i)
5x=3y-3...(ii)
Putting y in (ii)
5x=3(2x-2)-2
5x=6x-6-2
5x=6x-8
-x=-8
x=8
putting x=8
y=2(8)-2
y=14
y=2x-2.....(i)
2x+7y=1....(ii)
Putting y in equation (ii)
2x+7(2x+7)=1
2x+14x+49=1
16x=--48
x=-4
when x=-4
y=2(-4)+7
y=-1

2007-09-13 19:27:18 · answer #9 · answered by Anonymous · 1 5

(eq1)
2x-y=2
(eq2)
5x-3y=3

(eq3)=(eq1)x3---> 6x-3y=6

eq3 - eq 2 ---> x=3, substitute back in the eq, y=4

and

(eq1)
y-2x=7
(eq2)
2x+7y=1

eq2 + eq 1 ---> y=1, substitute back in the eq, x=-3

2007-09-13 19:25:48 · answer #10 · answered by thatnaweedguy 1 · 1 4

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