Algebra question?

Question

The length of a rectangular garden is three times its width; if the area of the garden is 75 square meters, what are its dimensions?



THANKS EVERYBODY

Answer 1

1. L = 3W
2. 75 = L x W > A = (L)(W)

First: substitute 3W with "L" in the 2nd equation.

75 = (L)(W)
75 = (3W)(W)
75 = 3W^2

Sec: isolate W^2 - divide both sides by 3 (when you move a term to the opposite side, always use the opposite sign).

75/3 = (3W^2)/3
75/3 = W^2
25 = W^2, or W^2 = 25

Third: isolate "W" & eliminate the exponent - find the square root of both sides.

√W^2 = +/- √25
W = +/- √5*5
W = +/- 5

The only possible solution is 5. Now, substitute 5 with "W" in the 1st equation.

L = 3(5) = 15

Solution: 5 x 15 meters

Answer 2

let length be l and the width be w
given that
l=3w
area of a rectangle = l*w=75
3w*w=75
3(w^2)=75
w^2=25
w=square root of 25
w=5 m

Therefore the length is
l=3w
l=3*5
l=15 m

The length of the garden is 15m and the width is 5m

Answer 3

l = 3w and l * w = 75 = 3 w * w

w = 5
l = 15

Answer 4

5X15