(X/4)/4 = X/16
The multiplicative inverse of (x-1)/4 is 4/(x-1).
The additive inverse of (x-1)/4 is -[(x-1)/4].
2007-09-13 17:02:00
·
answer #1
·
answered by koi goldfish 2
·
1⤊
0⤋
No, it's x/16. (x/4)/(1/4) = x
2007-09-14 00:02:25
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
man you go all wrong from the beginning..
from the last:
(x/4)/4 IS NOT x
(imagine, you got x divided by 4 THEN divided AGAIN by 4, so it's x/16 for sure)
(((x/4) +1) -1) IS NOT (x/4) / 4
do it from outer ring you'll get x/4.
I think inverse of (x-1) / 4 is 4/(x-1) NOT (((x/4) +1) -1).
2007-09-14 00:07:26
·
answer #3
·
answered by redy_salem 2
·
1⤊
0⤋
Nope. Switch the x and y variables and solve for y. I got 4x+1 =y. That is how inverse functions are found. It isn't necessarily the inverse of the number.
2007-09-14 00:15:39
·
answer #4
·
answered by james w 5
·
0⤊
1⤋
(x / 4) / 4 = x / 16
2007-09-15 06:28:37
·
answer #5
·
answered by Como 7
·
1⤊
0⤋
let (x / 4) = a
hence, it ll bcom a / 4 or a times 1 /4
therefore, it ll bcom x / 4 times 1 / 4
which is x / 16
2007-09-14 00:00:50
·
answer #6
·
answered by frederick_leong87 1
·
0⤊
0⤋
I don't think that the inverse of (x-1)/4 is x.
x = (y - 1)/4
4x = y - 1
y = 4x + 1
Right?
2007-09-14 00:07:41
·
answer #7
·
answered by cjcourt 4
·
0⤊
0⤋
Yes
x / 4 / 4 = x/4 ( 4 /1 )= x
2007-09-14 00:01:08
·
answer #8
·
answered by Joseph 1
·
0⤊
1⤋
yes, (x/4)/4 is equal to x.
2007-09-13 23:58:57
·
answer #9
·
answered by Craig W 1
·
0⤊
1⤋