(x^2-5x+5)^x^2-9x+20=1
2007-09-13 15:32:59 · 6 answers · asked by lattekiwi 1 in Science & Mathematics ➔ Mathematics
X=5, X=4, X=4, X=1 (I believe that some numbers can be repeated depending on the problem)
2007-09-13 15:41:18 · answer #1 · answered by Ida R 2 · 0⤊ 0⤋
did you mean (x^2-5x+5)^(x^2-9x+20)=1?
you said you get x=5 and 4, can you check it? substitute one of them into the equation, i dont see that would equal to 1.
2007-09-13 15:56:34 · answer #2 · answered by ۞_ʞɾ_ 6 · 0⤊ 1⤋
Hint: 1 to any power is equal to 1.
2007-09-13 15:48:57 · answer #3 · answered by Demiurge42 7 · 0⤊ 0⤋
make it both in negatif form too
x=5 or x=-5
x=4 or x=-4
so there are 4 answers
2007-09-14 03:40:17 · answer #4 · answered by Polar 2 · 0⤊ 0⤋
faulty question
2007-09-13 19:36:23 · answer #5 · answered by Mugen is Strong 7 · 0⤊ 0⤋
duh
2007-09-13 15:35:33 · answer #6 · answered by Anonymous · 0⤊ 5⤋