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The position of a small object is given by X=34+10t+2t^3, where t is in seconds and x in meters.

what is the average velocity of the object between 0 and 3.0s? at what time between 0 and 3.0s is the instantaneous velocity zero?

2007-09-13 12:42:30 · 1 answers · asked by Mimi 1 in Science & Mathematics Physics

x is a function of t when graphed t=0 to t=3.0.

2007-09-13 17:46:40 · update #1

1 answers

instantaneous velocity is
dX/dt=10+6*t^2

This is never zero for any value of t

did you pose the question correctly?

if x(t)=34+10t-2t^3
then v(t)=10-6*t^2
v(t)=0 when t= sqrt(10/6)
or t=1.3 seconds

j

2007-09-14 06:12:21 · answer #1 · answered by odu83 7 · 0 0

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