What volume would be occupied by a piece of aluminum (d=2.70g/cm^3) weighing 85g?
Thanks SOOO much your help im really confused on this problem :)
2007-09-13 12:29:42 · 6 answers · asked by CrimsonRider 1 in Science & Mathematics ➔ Mathematics
density = mass / volume
so
volume = mass / density
V = 85 g / 2.70 g/cm^3 = 31 cm^3
Also your answer should only have 2 significant digits because that's the least number of significant digits involved in the problem information (the mass has 2 significant digits, the density has 3).
2007-09-13 12:32:20 · answer #1 · answered by cjcourt 4 · 0⤊ 0⤋
density = mass / volume
2.70 g/cm^3 = 85g / V
V = 85g / 2.70 g/cm^3
V= 31.48 cm^3 (grams cancel out)
2007-09-13 13:14:00 · answer #2 · answered by Jay w 2 · 0⤊ 0⤋
d(density) = mass over volume
therefore
volume = mass over density
V = 85g/2.7g/cm^3
V = ... cm^3
2007-09-13 12:35:56 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Why are you confused?
D = grams per cubic cm
how many cubic cm is 85/2.7
2007-09-13 12:34:56 · answer #4 · answered by Anonymous · 0⤊ 0⤋
85/2.7=31.481 cm^3
2007-09-13 12:37:54 · answer #5 · answered by David 4 · 0⤊ 0⤋
V = m/δ = 85/2.70 = 31.5 cm³
2007-09-13 12:33:27 · answer #6 · answered by gebobs 6 · 0⤊ 0⤋