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lim (x --> infinity) (10x^2 + 25x + 1)/(x^4 - 8)

2007-09-13 12:25:19 · 1 answers · asked by pixiestix 1 in Science & Mathematics Mathematics

how does the numerator = 1, and the denominator = 0?

2007-09-13 12:42:08 · update #1

i mean, the other way around

2007-09-13 12:42:23 · update #2

1 answers

= (10/x^2+25/x^3+1/x^4)/(1-8/x^4)
All summands of the numerator ==>0 and the denominator=>1
so the limit is 0

2007-09-13 12:34:01 · answer #1 · answered by santmann2002 7 · 0 0

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