If I have a 5"x5" box and I want there to be 3 rows of small boxes and 3 columns of small boxes, what would be the height and width of the small boxes?
Thanks
2007-09-13 12:15:45 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5/3" ~ 1-5/8
2007-09-13 12:23:00 · answer #1 · answered by gebobs 6 · 0⤊ 1⤋
If the width of your large box is 5 inches and you divide it into 3, you'll get 5/3 which is the same as 1 and 2/3.
That means each small box has a width of 1 and 2/3"
Since you do the same for the height, the height of the small boxes would also be 1 and 2/3" (This is the same, in decimal form as 1.666666...but repeating decimals are useless in measurement. It's much easier to measure two-thirds!)
You can check easily. If each small box is 1 and 2/3 inches by 1 and 2/3 inches, multiply the two together:
1 2/3 x 1 2/3 = 5/3 x 5/3 = 25/9 (Twenty-five is the square area of your large box and nine is the number of small boxes! ((((-: )
(I'm not sure how gebob is getting 1 and five-eighths from 5/3
5 over 3 gives you 1 whole and two thirds left over....)
2007-09-13 12:36:16 · answer #2 · answered by GeriGeri 5 · 0⤊ 0⤋
Divide 5" by 3. Since the box is 5X5, the length and width will be the same.
2007-09-13 12:24:15 · answer #3 · answered by gilliegrrrl 6 · 0⤊ 0⤋
5 inches divided by 3 rows= 5/3
The new smaller boxes will be 5/3" x 5/3"
5/3 = 1 2/3 = 1.667 inches between dividers.
2007-09-13 12:25:24 · answer #4 · answered by Matthew Stewart 5 · 0⤊ 0⤋
In other words, you want 9 boxes in a 25" square.
So you divide 9 into 25. It's about 2.7777778, then divide it by two. Rounding aside, leaves you about 1.4" each.
2007-09-13 12:24:08 · answer #5 · answered by KC_Meag42 5 · 0⤊ 1⤋