(3x squared , y to the third) to the power of negative 2?

Question

how do you simplify this problem?

Answer 1

1 / [ ( 3 x ² ) y^(1/3) ] ²
1 / [ 9 x^(4) y^(1/6) ]

Answer 2

ok Claudia-- Is it (18x)^4 or 18*x^4? and is it (6x)^5 or 6*x^5? I'll do it both ways. 1. (18x)^4*y^-3*z^2/(6x)^5*y^2*z 2. 18^4*x^4*z^2/6^5*x^5*y^5*z 3. 6^4*3^4*x^4*z^2/6^5*x^5*y^5*z. Now cancelling what you can you get Answer = 27z/2xy^5 The other way. 1. 18*x^4*y^-3*z^2/6*x^5*y^2*z 2, 18*x^4*z^2/6*x^5*y^5*z 3. Now cancelling what you can you get Answer = 3z/xy^5

Answer 3

(3x^2 y^3)^-2


the answer is 1/ 9x^4^6