x^2=(5-2x)(-x) move x squared over
x^2=(-5x+2x^2) distribute -x
x=-5+2x divide both sides by x
-x=-5 move 2x over
x=5 divide both sides by -1 to get positive answers
2007-09-13 11:54:14
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answer #1
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answered by bob 2
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Simplified, this equation becomes:
(-5x + 2x[square]) + x[square]
Then, take away parenthesis and combine x[square] terms:
3x[square] - 5x
Then, you can factor out the x to get:
x(3x-5)
I'm not sure exactly what kind of answer you were looking for, but I hope this helps.
2007-09-13 11:46:42
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answer #2
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answered by Madadivad 2
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(5-2x)(-x) +x^2 FOIL
-5x + 2x^2 +x^2 Combine like terms
-5x + 3x^2 Make it look nice
3x^2 - 5x You can factor out an x if you want to
x(3x-5)
2007-09-13 11:49:41
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answer #3
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answered by m3_mY$3Lf_! 4
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distribute -x with 5-2x
-5x+2x^2+ x^2
add like terms
3x^2-5x
2007-09-13 11:47:03
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answer #4
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answered by Anonymous
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= -5x + 2x² + x²
= 3x² - 5x
= x(3x - 5)
2007-09-13 11:46:19
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answer #5
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answered by gebobs 6
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what does x represent?if it doesn't represent anything,then it would be simplified as 5-3x+xsquared
2007-09-13 11:47:50
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answer #6
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answered by imjustakid&lifeisanitemare 4
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wouldnt the answer be -5x + 3x(squared)??
i dunno i did a-level maths.. lol
2007-09-13 11:47:06
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answer #7
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answered by baby_girl 1
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