Algebra Review?

Question

I understand how to do the basic common denominator problems like the last one:

5/(x+2)-9/(x+2)

But the real problem is when the numbers added to x are different, that makes the problem more complex like this one right here:

3/(x+2)=2/(x+5)

What would be the first few steps in solving this problem?
(Please don't solve the whole thing, just show how to get rid of the fractioned x)

thanks again!

Answer 1

Question 1
5 / (x + 2) - 9 / (x + 2)
= ( - 4 ) / (x + 2)

Question 2
3 / (x + 2) = 2 / (x + 5)
3 (x + 5) = 2 (x + 2)
3x + 15 = 2x + 4
3x - 2x = 4 - 15----to be finished,as requested

Answer 2

Your LCD is (x+2)(x+5).
Multiply the first term by (x+5)/(x+5).
Multiply the second term by (x+2)/(x+2)
Once you've done that, you can disregard the denominators because they are the same; so you just have the first numerator = the second numerator.
Solve for x.
I won't give you the answer since you didn't ask for it.