2007-09-13 10:59:49 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x - 3) (x - 1) = 0
x = 3 , x = 1
2007-09-14 20:20:12 · answer #1 · answered by Como 7 · 2⤊ 0⤋
This is a quadratic equation. In order to solve it, you have to reverse the FOILing process:
(x-3)(x-1)=0
If you multiply this out, it'll equal x^2-4x+3=0
Now, you can subsitute x with anything that'll make the equation true. So:
3-3=0 there fore if x=3, the equation would be true
Because this is a quadratic equation, x can have two values.
1-1=0 as well, so there fore x can =3 and 1
Now to finalize and check your answer, just plug in each of your possible x values:
3^2-4(3)+3=0
=9-12+3=0
=-3+3+0
=0=0...equation works
1-4+3=0
=-3+3=0
=0=0...equation works
Hopes this helps!
2007-09-13 11:15:07 · answer #2 · answered by gotriceazn101 2 · 0⤊ 1⤋
Factor the problem:
(x+1)(x+3)=0
Set each problem equal to zero:
(x+1)=0 (x+3)=0
Subtract 1 and 3 from each equation:
x=-1 x=-3
2007-09-13 11:06:16 · answer #3 · answered by megcapri1107 3 · 0⤊ 1⤋
X= 3 and/or 1 because it becomes (X-3)(X-1)
2007-09-13 11:05:04 · answer #4 · answered by Anonymous · 0⤊ 0⤋
either 3 or 1
2007-09-13 11:04:03 · answer #5 · answered by Anonymous · 1⤊ 0⤋
(x-3)(x-1) = 0
so x = 1 or x = 3
2007-09-13 11:05:13 · answer #6 · answered by ? 7 · 0⤊ 0⤋
Would be 3 because of the carrot.
2007-09-13 11:05:07 · answer #7 · answered by isaac f 3 · 0⤊ 0⤋
(x-1) (x-3) = 0
(x-1)=0
x = 1
(x-3)=0
x = 3
2007-09-13 11:04:41 · answer #8 · answered by Anonymous · 0⤊ 0⤋
1.2-8*4(658).
2007-09-13 11:05:13 · answer #9 · answered by Anonymous · 0⤊ 0⤋
do your own bloody stickin homework!!!!!!! lol but it would be better if you said what grade your in so people younger don't answer wrong! but any way I the answer would be .............
1 !!!!!!!
2007-09-13 11:09:41 · answer #10 · answered by me 5 · 0⤊ 1⤋