benzoic acid, easy to look up what it looks like.
my question is... when benzoic acid reacts with naoh, it reacts with the oh, the oh takes the H from the oh thats attached to benzoic acid. NOW the NEW o that has 1 bond and 6 electrons around it, is attached to a carbon that is FULL, does it create a double bond and over fill the carbon, or does the molecule stay with a negative charge, i dont understand the rules for when a carbon can have an over full shell.
PLEASE HELPPPP
2007-09-13 07:40:09 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
C6H5COOH + NaOH ===> C6H5COO-Na+ + H2O
The (-) charge is distributed half on each O by resonance. It's as if there were a rapid change between C=O and C-O(-), with each O getting to be -O(-) half the time. Another way to look at it is that each bond is a 1-1/2 bond, C-O plus C***O, with each O 1/2(-) all the time.
In the first resonance explanation, each atom has a full shell in each structure. In the second explanation, each atom has a full shell, because there are 3/2 electrons in the bonds and 1/2(-) on the O.
2007-09-13 07:50:06 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋
C6H5COOH --> C6H5COO- + H+
It is the H+ from benzoic acid that reacts with the OH- from NaOH to form water
It is the Na+ that takes the place of the H+ from benzoic acid; there is no "new" oxygen attached to the carbon.
2007-09-13 07:46:44 · answer #2 · answered by skipper 7 · 0⤊ 0⤋