2007-09-13 07:30:28 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Are you asking to simplify? If so, add the x terms together and the -5 and +9 together you will have:
3x^2+6x+4.
If you are to set it equal to zero and solve for x, you will need to use the quadratic formula because this cannot be factored.
2007-09-13 07:38:40 · answer #1 · answered by The Light One 3 · 0⤊ 0⤋
I assume you mean: 3x^2 + 4x - 5 + 2x + 9 = 3x^2 + 6x + 4
2007-09-13 07:43:35 · answer #2 · answered by nine 1 · 0⤊ 0⤋
3x^2 + 4x - 5 + 2x + 9
Add like terms
3x^2 + 6x + 4 => answer
2007-09-13 07:41:04 · answer #3 · answered by lenpol7 7 · 0⤊ 0⤋
I don't know. You tell me what that's supposed to be equal to.
If you want to know how to simplify it, then combine like terms. The 4x and 2x can be combined, as can the -5 and 9.
2007-09-13 07:38:07 · answer #4 · answered by Anonymous · 0⤊ 0⤋
3x2+4x+2x+9-5
=>3x2+6x+4
assumin that u r in need of findin the factors , i am proceedin further,
3x2+6x+4=0
for the eqn ax2+bx+c=0 the roots are [-b (+or-) sqrt(b^2 -4ac) ] / (2a)
here a = 3, b=6 , c= 4 ,sub and solve
u get
[-6 (+ or -) sqrt(36-4*3*4)] / 6
= [-6 (+ or -) sqrt(-12)] / 6
=[-6 (+ or -) i sqrt(4 * 3)] / 6
=[-6 (+ or -) i 2sqrt(3)] / 6
=2[-3 (+ or -) i sqrt(3)] / 6
= [-3 (+ or -) i sqrt(3)] / 3
= -1 (+ or -) i sqrt(3) / 3
2007-09-13 07:42:29 · answer #5 · answered by Serenity 2 · 0⤊ 0⤋
A second degree in x
2007-09-13 07:39:35 · answer #6 · answered by Tao N 2 · 0⤊ 0⤋