sqrt22/sqrt55=(sqrt2*sqrt11)/(sqrt5*sqrt11)
=sqrt 2/sqrt 5 [Since sqrt 11 cancels]
2007-09-13 06:08:35
·
answer #1
·
answered by Divi 2
·
0⤊
1⤋
Rationalize the denominator.
√22/√55
First: multiply the denominator with the fraction.
(√55)(√22)/(√55)(√55)
√(1,210)/√(3,025)
Sec: simplify the numbers into lowest terms. At this step, you don't cross cancel any terms.
√(2*5*11*11)/√(5*5*11*11)
Third: when a number is repeated twice, place it (once) in front of its radical sign & combine the rest.
(11√10)/5*11
(11√10)/55
2007-09-13 06:12:53
·
answer #2
·
answered by ♪♥Annie♥♪ 6
·
0⤊
0⤋
= √2√11/√5√11
= √2/√5
2007-09-13 06:08:18
·
answer #3
·
answered by gebobs 6
·
0⤊
1⤋
Multiply by sqrt 55 / sqrt 55
Sqrt 1210 / 55
You can probably simplify the fraction even further.
*Using PMP's answer*
sqrt 2 / sqrt 5
Multiply by sqrt 5 on both sides.
sqrt 10 / 5
2007-09-13 06:07:08
·
answer #4
·
answered by MathDude356 3
·
0⤊
1⤋
sqrt(22) = sqrt(2 * 11) = sqrt(2) * sqrt(11)
sqrt(55) = sqrt(5 * 11) = sqrt(5) * sqrt(11)
The "sqrt(11)" cancels out on top and on the bottom.
sqrt(2)/sqrt(5)
To rationalize the denominator, multiply through by sqrt(5) on top and on the bottom. You'll get...
sqrt(10) / 5
2007-09-13 06:06:52
·
answer #5
·
answered by PMP 5
·
0⤊
1⤋
h(x) = 4(x+3)^2 + 7 the reason for it incredibly is a horizontal translation gets subtracted from x. A shift of -3 outcomes interior the previous function considering x -(-3) = x +3. A vertical shift gets subtracted from y. So, in case you wanted to shift it 3 gadgets up, it would appear as if this: h(x) - 3 = 4x^2 +7, and you will in simple terms remedy for h(x) to yield h(x) = 4x^2 + 10.
2016-10-10 12:25:10
·
answer #6
·
answered by kuder 4
·
0⤊
0⤋
sqrt22/sqrt55=sqrt(22/55)=sqrt(2/5)=sqrt(2)/sqrt(5)=sqrt(0,4)
2007-09-13 06:07:16
·
answer #7
·
answered by ?????? 7
·
0⤊
1⤋
sqrt22=sqrt2*sqrt11
sqrt55=sqrt5*sqrt11
sqrt22/sqrt55
=(sqrt2*sqrt11)/(sqrt5*sqrt11)
=sqrt2/sqrt5
2007-09-13 06:08:46
·
answer #8
·
answered by Andrew M 2
·
0⤊
1⤋