How many grams are there in 1.00L of alcohol if density is 0.78945 g/cm^3? (1mL = 1 cm^3)
2007-09-13 05:06:11 · 7 answers · asked by jobroluvr=)<3 1 in Science & Mathematics ➔ Chemistry
0.76845 g/ml *1000 ml = 768.5 g alcohol
2007-09-13 05:10:31 · answer #1 · answered by Dr Dave P 7 · 0⤊ 0⤋
The answer is a straight forward proportion, if there are 0.78945 g in 1 mL how many are there in 1000 mL (or 1 L)?
the answer would be 789.45g
2007-09-13 12:12:18 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1 cm^3 = 1mL
1 L = 1000mL
Therefore, to cancel the mL out on the bottom of the given density we can leave ourselves with mass (grams):
0.78945 g/mL * 1000mL = 789.45g alcohol
(above the mL cancel and the units you are left with is g)
2007-09-13 12:10:12 · answer #3 · answered by ScienceNut 2 · 0⤊ 0⤋
D=M/V where D=density, M= mass and V=volume. 1L=1000mL=1000cm^3.
M=DV=0.78945 X 1000=789.45g
2007-09-13 12:12:31 · answer #4 · answered by Boogie0821 2 · 0⤊ 0⤋
1 Liter is 1000 milli liters and each ml weigs 0.78945 g (one ml and one cc are same). So, multiply the density to get the weight.
789.45 grams
2007-09-13 12:11:25 · answer #5 · answered by Swamy 7 · 0⤊ 0⤋
Convert liters to milliliters, then multiply it out.
(1.00 L)(1000 ml/L)(0.78945 g/mL) = ???
Notice how the units cancel out. Liters is the denominator in one parenhtesis, the numerator in another. That causes it to cancel out, leaving mL. mL is cancelled out in the next step, leaving you with grams.
2007-09-13 12:09:32 · answer #6 · answered by Brian L 7 · 0⤊ 0⤋
789.45g
2007-09-13 12:12:13 · answer #7 · answered by Anonymous · 0⤊ 0⤋