they are simple sugars and i will like to knowthe tests(chemical) for differenciating the two.
2007-09-13 03:44:06 · 5 answers · asked by adanna 1 in Science & Mathematics ➔ Chemistry
Aldoses, which have an aldehyde group on the first carbon atom, and ketoses, which typically have a ketone group on the second. They may also be divided into trioses, tetroses, pentoses, hexoses, and so forth, depending on how many carbon atoms they contain. For instance, glucose is an aldohexose, fructose a ketohexose.
It should be noted that the ring form has one more optically active carbon than the straight-chain form, and so has both an alpha and a beta form, which interconvert in equilibrium. However, the carbohydrate may further react with an alcohol to form an acetal or ketal, in which case the two forms become distinct. This is the basic type of link between the monosaccharide units of larger carbohydrates
As far as more tests go, check out the organic part of this page and see if it offers some ideas:
http://www.wpbschoolhouse.btinternet.co.uk/page13/ChemicalTests/ChemicalTests.htm
2007-09-13 03:52:26 · answer #1 · answered by originalsmartie 4 · 2⤊ 0⤋
Yes they are; one is an aldehyde and the a ketone in the simplest structure that can be drawn. The aldehyde on Carbon 1 or 6, then ketone on Carbon 2 or 5; that puts them into the carbohydrate or sugar class, no ketone on any other Carbon in the chain.
Another contributor is correct; Fehling's is a good differentiator.
2007-09-13 04:31:42 · answer #2 · answered by vv 6 · 0⤊ 0⤋
Sounds like a Weekend at the Professor's house.
2016-03-13 04:03:56 · answer #3 · answered by Anonymous · 0⤊ 0⤋
3 letters
2007-09-13 03:52:04 · answer #4 · answered by Anonymous · 1⤊ 0⤋
Fehling and Tollen's test.
2007-09-13 04:01:56 · answer #5 · answered by ag_iitkgp 7 · 0⤊ 0⤋