If electrons constantly vibrate(uncertainty principle), then...?

Question

If electrons constantly vibrate(uncertainty principle), and since moving charges emit photons (from the virtual photons left behind), shouldn't all electrons be constantly giving "free" energy?

Answer 1

Electrons orbit the Nucleus of the Atom. If the electron is forced toward the Nucleus if would increase in orbital velocity. If the electrons gets closer and closer to the nucleus if will lose mass as micromass radiation. That means the electron is constinously subject to change mass as the atom's temperature charges.
If charge of the electron is defined in terms of its mass ,then it means that charge is variable within certain limits as a function of temperature. However; In an electrical circuit electrons lose charge due to friction.
As far as electron giving free energy= Nothing in this Universe is obtained without paying a price.(2nd law of thermodynamics.)
As far as Heisenberg's Uncertainty principle is concerned its just a formulation of measurement , which basically indicates that we cannot measure the instanatenous velocity of any type of motion. In real life we can only measure averages= that is where the whole uncertainty principle revolves in essence.
On the basis of the Uncertainty principle, Niels Bohr Energy levels in the Hydogen atoms are not really real because the electron moves in three dimensional motion. And it its impossible to determine the actual positon of the electron and its rotational energy at the same time while in orbital motion.

Answer 2

No, electrons also absorb photons when the move up energy levels, they then emit photons when they descend energy levels - you cannot get 'free energy' as electrons also must obey the conservation of energy principle.

Heisenberg's uncertainty principal simply states that it is impossible to exactly predict where the electron (or particle) is situated, but gives the most probable location; this relates to (planck's constant / 2 * pi) which is a tiny number of the order 10^-34 metres.

We cannot measure distances this small and therefore we just use Quantum mechanics and probability theory to determine the 'best guess' where the particle is.

Answer 3

No.

First, electrons are not "vibrating" in the classical way you're thinking about. What is really happening is that their position and momentum is spread out over a range of values. The "wave function" that describes this range of positions and momenta oscillates in value, but this is not the same thing as the electron vibrating. In many cases, the oscillation of the wave function doesn't even represent an observable phenomenon.

Second, the rule "accelerating charges emit photons" is not correct. It is only valid macroscopically. The correct quantum mechanical rule is that charges emit/absorb photons when they change energy states.