intercepts of a plane?

Question

Find the x, y and z intercepts of the plane -2y+z-1=0

the exuation does not really have an x term. Though you can consider
0x -2y +z-1=0.

Answer 1

-2y+z-1=0

this one does not have x-intercept, it is parallel to the line y=0, z=0.

z=0, then -2y -1 =0 so y = -1/2
and if
y =0, then z-1 =0, so z =1.

Answer 2

To find the intercepts, set all the other variables equal to zero and solve for the remaining one.

0 - 2y + 0 - 1 = 0
-2y = 1
y = -1/2

0 - 2*0 + z - 1 = 0
z = 1

There is no x intercept.

The intercepts are:

x = none
y = (0, -1/2, 0)
z =(0, 0, 1)

Answer 3

Your formula for the plane should have an x term in it. Update the question to include this and I will answer it.