An empty Erlenmeyer flask weighs 264.3 g. When filled with water (d = 1.00 g/cm3), the flask and its contents weigh 500.3 g.
a) What is the flask's volume?
b) How much does the flask weigh when filled with chloroform (d = 1.48 g/cm3)?
2007-09-12 16:07:15 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
a) The increase in weight of the flask, which is due to the water in it, is 500.3g - 264.3g = 236.0g. We are told that the density of water is 1.00g/cm^3; therefore the volume of the flask is:
236.0g / (1.00 g/cm^3) = 236.0 cm^3
(I'll use cc for cubic centimeters from here.)
b) The volume, determined in (a), is 236.0 cc. The density of chloroform is given as 1.48 g /cc. Therefore the weight of the filled flask is the weight of the empty flask plus the weight of the chloroform in it:
264.3 g + ( 236.0 cc x 1.48 g/cc) = 264.3 g + 349.3 g
= 613.6 g
2007-09-12 16:22:56 · answer #1 · answered by richg74 3 · 0⤊ 0⤋
Those little "d=" should be a hint. Density= weight/volume. So........
For water, the water weight (full flask-empty)in g divided by 1 g/cc = volume in cc
Once you have that, you can MULTIPLY the volume by density to get weight of chemical. Then add back on the weight of the flask.
2007-09-12 23:19:28 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
500.3 g full - 264.3 g empty = 236.0 g of water
236 g / 1.000 g/cm^3 = 236.0 cm^3 of water
the volume is 236.0 cm^3
236.0 cm^3 x 1.48 g/cm^3 = 349.3 g when full of chloroform
this problem was asked about 15 minutes ago with a different filled weight...504.3 if I remember correctly
2007-09-12 23:15:08 · answer #3 · answered by skipper 7 · 0⤊ 0⤋
a. 236ml
b. 613 g
2007-09-12 23:13:34 · answer #4 · answered by alyssia_o6 1 · 0⤊ 1⤋