Physics Question?

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A sports car is advertised to be able to stop in a distance of 50 m form a speed of 90 km/h. What is its acceleration in m/s^2. How many g's is this (g=9.80 m/s^2).

2007-09-12 16:02:53 · 1 answers · asked by nirmal 1 in Science & Mathematics ➔ Physics

1 answers

Apply the formula

x = (v^2-v0^2)/(2a) ---> a = (v^2-v0^2)/(2x)

a = (v^2-v0^2)/(2x) = [(90km/hr)^2 - 0]/(2*50m)

90 km/hr = 90,000 m/(3600 s) = 25 ms/

a = 625m^2/s^2/100 m =6.25 m/s^2

2007-09-12 16:09:35 · answer #1 · answered by nyphdinmd 7 · 0⤊ 0⤋