Factor each of the following polynomials completely -3s^2-10x+8
2007-09-12 15:57:10 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
I think you have typed wrongly.the polynomial should be -3s^2-10s+8 and not -3s^2-10x+8.
assuming that I am right,I am factoring below
-3s^2-10s+8
= -(3s^2+10s-8)
= -(3s^2+12s-2s-8)
= -{3s(s+4)-2(s+4)}
= -(s+4)(3s-2)
2007-09-12 16:07:42 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
Perhaps the equation should be like this then the answer is
-3x^2-10x+8=0
-3x^2-12x+2x+8=0 {Find the factors -> the factors are -12 &2}
-3x(x+4)+2(x+4)=0
(-3x+2)(x+4)=0
-3x+2=0 or x+4=0
-3x=-2 or x=-4
x= 2/3 or x= -4
2007-09-12 19:57:07 · answer #2 · answered by Divi 2 · 0⤊ 0⤋
This can't be factored as it is written. There are 2 different variables. If they are supposed to be the same then -1(3s-2)(s+4)
2007-09-12 16:11:22 · answer #3 · answered by Nelson_DeVon 7 · 0⤊ 0⤋
were the eqn. (you have specified two variables 's' and 'x' )
-3x^2 -10x +8 the proceed this way
=-3x^2 -12x + 2x +8
=-3x(x+4)+2(x+4)
=(-3x+2)(x+4)
2007-09-12 16:08:48 · answer #4 · answered by vcs7578 5 · 0⤊ 0⤋